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Question
If the lengths of the sides of a triangle are in A.P. and the greatest angle is double the smallest, then a ratio of lengths of the sides of this triangle is ______.
Options
5 : 9 : 13
4 : 5 : 6
3 : 4 : 5
5 : 6 : 7
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Solution
If the lengths of the sides of a triangle are in A.P. and the greatest angle is double the smallest, then a ratio of lengths of the sides of this triangle is 4 : 5 : 6.
Explanation:
Let the sides of triangle be a > b > c where
Given A = 2C
∵ A + B + C = π and A = 2C
`\implies` B = π – 3C ...(i)
∵ a, b, c are in A.P. `\implies` a + c = 2b
`\implies` sin A + sin C = 2 sin B ...(ii)
`\implies` sin A = sin (2C) and sin B = sin 3C
From (ii),
sin 2C + sin C = 2 sin 3C
`\implies` (2cos C + 1) sin C = 2 sin C (3 – 4 sin2C)
`\implies` 2cos C + 1 = 6 – 8 (1 – cos2C)
`\implies` 8cos2C – 2cos C – 3 = 0
`\implies` cos C = `3/4` or cos C = `-1/2`
∵ C is acute angle
`\implies` cos C = `3/4 \implies` sin C = `sqrt(7)/4`
and sin A = 2 sin C cos C = `2 xx sqrt(7)/4 xx 3/4 = (3sqrt(7))/8`
sin B = `(3sqrt(7))/4 - (4sqrt(7))/4 xx 7/16 = (5sqrt(7))/16`
`\implies` sin A : sin B : sin C : : a : b : c is 6 : 5 : 4
