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If the angle between the tangent t The circle x2 + 42 + 2x + 4y – 11 = 0 from p(3, 3) is tan-1(ab) where a and b are relatively prime then the value of a – 3b is ______.

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Question

If the angle between the tangent t The circle x2 + 42 + 2x + 4y – 11 = 0 from p(3, 3) is  `tan^-1(a/b)` where a and b are relatively prime then the value of a – 3b is ______.

Options

  • 15

  • 0

  • 13

  • 8

MCQ
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Solution

If the angle between the tangent t The circle x2 + 42 + 2x + 4y – 11 = 0 from p(3, 3) is  `tan^-1(a/b)` where a and b are relatively prime then the value of a – 3b is 13.

Explanation:

Centre C(–1, –2) radius = 4


QP = 5 tanθ = `4/5`

2Q = `tan^-1((2.4.5)/(25 - 16))` = `tan^-1(40/9)`

a = 40, b = 9

⇒ a – 3b = 13

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