Question

If the activation energy for the forward reaction is 150 kJ mol⁻¹ and that of the reverse reaction is 260 kJ mol⁻¹, what is the enthalpy change for the reaction?

Options

• 410 kJ mol⁻¹

• −110 kJ mol⁻¹

• 110 kJ mol⁻¹

• −410 kJ mol⁻¹

Answer 1

−110 kJ mol⁻¹

Explanation:

For a reversible reaction,

ΔH = E_a (forward) − E_a (backward)

= 150 − 260

= −110 kJ mol⁻¹