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If the 3rd and the 9th term of an A.P. be 4 and –8 respectively, find which term is zero?

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Questions

If the 3rd and the 9th term of an A.P. be 4 and –8 respectively, find which term is zero?

If the 3rd and the 9th terms of an arithmetic progression are 4 and −8 respectively, which term of it is zero?

Sum
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Solution

For an A.P., a

t3 = 4

`=>` a + 2d = 4  ...(i)

t9 = – 8

`=>` a + 8d = – 8  ...(ii)

Subtracting (i) from (ii), we get

6d = –12

`=>` d = –2

Substituting d = –2 in (i), we get

a + 2(–2) = 4

`=>` a – 4 = 4

`=>` a = 8

`=>` General term = tn = 8 + (n – 1)(–2)

Let pth term of this A.P. be 0

`=>` 8 + (p – 1) × (–2) = 0

`=>` 8 – 2p + 2 = o

`=>` 10 – 2p = 0

`=>` 2p = 10

`=>` p = 5

Thus, 5th term of this A.P. is 0

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Chapter 10: Arithmetic Progression - TEST YOURSELF [Page 143]

APPEARS IN

Selina Concise Mathematics [English] Class 10 ICSE
Chapter 10 Arithmetic Progression
TEST YOURSELF | Q 3. | Page 143
Selina Concise Mathematics [English] Class 10 ICSE
Chapter 10 Arithmetic Progression
Exercise 10 (B) | Q 6. | Page 136
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