English
Maharashtra State BoardSSC (English Medium) 10th Standard

If sin θ + sin2 θ = 1 show that: cos2 θ + cos4 θ = 1

Advertisements
Advertisements

Question

If sin θ + sin2 θ = 1 show that: cos2 θ + cos4 θ = 1

Sum
Advertisements

Solution

sin θ + sin2 θ = 1 ......[Given]

∴ sin θ = 1 − sin2 θ

∴ sin θ = cos2 θ ......[∵ 1 − sin2 θ = cos2 θ]

∴ sin2 θ = cos4 θ ......[Squaring both the sides]

∴ 1 − cos2 θ = cos4 θ ......[∵ sin2 θ = 1 − cos2 θ]

∴ 1 = cos2 θ + cos4 θ

∴ cos2 θ + cos4 θ = 1

shaalaa.com
  Is there an error in this question or solution?
2019-2020 (March) Official

RELATED QUESTIONS

Prove the following identities, where the angles involved are acute angles for which the expressions are defined.

`(sintheta - 2sin^3theta)/(2costheta - costheta) =tan theta`

 


Prove the following trigonometric identities.

sin2 A cot2 A + cos2 A tan2 A = 1


Prove the following identities:

(1 + tan A + sec A) (1 + cot A – cosec A) = 2


Prove that:

(cosec A – sin A) (sec A – cos A) sec2 A = tan A


`1/((1+tan^2 theta)) + 1/((1+ tan^2 theta))`


`sec theta (1- sin theta )( sec theta + tan theta )=1`


`(cot^2 theta ( sec theta - 1))/((1+ sin theta))+ (sec^2 theta(sin theta-1))/((1+ sec theta))=0`


Write the value of `cosec^2 theta (1+ cos theta ) (1- cos theta).`


 Write True' or False' and justify your answer  the following : 

The value of  \[\sin \theta\] is \[x + \frac{1}{x}\] where 'x'  is a positive real number . 


Prove the following identity :

`sec^2A.cosec^2A = tan^2A + cot^2A + 2`


Prove the following identities:

`(sec"A"-1)/(sec"A"+1)=(sin"A"/(1+cos"A"))^2`


Prove the following identity : 

`(tanθ + 1/cosθ)^2 + (tanθ - 1/cosθ)^2 = 2((1 + sin^2θ)/(1 - sin^2θ))`


Prove that: sin4 θ + cos4θ = 1 - 2sin2θ cos2 θ.


If `tan θ = 9/40`, complete the activity to find the value of sec θ.

Activity:

sec2θ = 1 + `square`   ...[Fundamental trigonometric identity]

sec2θ = 1 + `square^2`

sec2θ = 1 + `square` 

sec θ = `square` 


Prove that `1/("cosec"  θ - cot θ) = "cosec"  θ + cot θ`.


If 3 sin θ = 4 cos θ, then sec θ = ?


tan2θ – sin2θ = tan2θ × sin2θ. For proof of this complete the activity given below.

Activity:

L.H.S. = `square`

= `square (1 - (sin^2θ)/(tan^2θ))`

= `tan^2θ (1 - square/((sin^2θ)/(cos^2θ)))`

= `tan^2θ (1 - (sin^2θ)/1 xx (cos^2θ)/square)`

= `tan^2θ (1 - square)`

= `tan^2θ xx square`   ...[1 – cos2θ = sin2θ]

= R.H.S.


If 1 + sin2α = 3 sinα cosα, then values of cot α are ______.


Prove the following that:

`tan^3θ/(1 + tan^2θ) + cot^3θ/(1 + cot^2θ)` = secθ cosecθ – 2 sinθ cosθ


(1 – cos2 A) is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×