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If sin θ = 2 cos θ, then (3 sin θ – cos θ)/(3 sin θ + cos θ) is equal to ______. - Mathematics

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Question

If sin θ = 2 cos θ, then `(3 sin θ - cos θ)/(3 sin θ + cos θ)` is equal to ______.

Options

  • 0

  • `1/2`

  • `2/5`

  • `5/7`

MCQ
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Solution

If sin θ = 2 cos θ, then `(3 sin θ - cos θ)/(3 sin θ + cos θ)` is equal to `underlinebb(5/7)`.

Explanation:

sin θ = 2 cos θ 

⇒ `tan θ = (sin θ)/(cos θ)`

= 2 

Equivalently set cos θ = c, sin θ = 2c and substitute:

`(3 sin θ - cos θ)/(3 sin θ + cos θ)` 

= `(3 xx 2c - c)/(3 xx 2c + c)` 

= `(6c - c)/(6c + c)`

= `(5c)/(7c)`

= `5/7`

The sign of c cancels, so the result is `5/7`.

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Chapter 17: Trigonometric Ratios - Exercise 17B [Page 362]

APPEARS IN

Nootan Mathematics [English] Class 9 ICSE
Chapter 17 Trigonometric Ratios
Exercise 17B | Q 7. | Page 362
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