Question

If the roots of the quadratic equation `px(x-2)+=0`  are equal, find the value of p

Answer 1

It is given that the roots of the quadratic equation` px^2-2px+6=0` 

are equal. 

∴`D=0` 

⇒`(-2p)^2-4xxpxx6=0` 

⇒`4p^2-24p=0` 

⇒`4p(p-6)=0` 

⇒`p=0  or  p-6=0` 

⇒`p=0  or  p=6` 

For p=0,we get 6 =0,  which is not true. 

∴ `p≠0` 

Hence, the value of p is 6.