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Question
If 'ΔQ' is the amount of heat supplied to 'n' moles of a diatomic gas at constant pressure, 'Δ U' is the change in internal energy and 'Δ W' is the work done, then Δ W : Δ U : Δ Q is ______.
Options
1 : 2 : 3
2 : 5 : 7
2 : 3 : 4
5 : 7 : 9
MCQ
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Solution
If 'ΔQ' is the amount of heat supplied to 'n' moles of a diatomic gas at constant pressure, 'Δ U' is the change in internal energy and 'Δ W' is the work done, then Δ W : Δ U : Δ Q is 2 : 5 : 7.
Explanation:
We know,
Δ Q = nCpΔT
Δ U = nCvΔT
W = P ΔV = nR ΔT
ΔW : ΔU : ΔQ = R : Cv : Cp
For a diatomic gas f = 5
`therefore "C"_"v" = "f"/2 "R" = 5/2 "R"`
Cp = Cv + R = `7/2`R
∴ R : Cv : Cp = 1 : `5/2 : 7/2` = 2 : 5 : 7
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Classification of Thermodynamic Processes
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