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Question
If log10 a = m, express the following in terms of a.
105m−3
Sum
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Solution
Given: log10 a = m
To find: Express 105m−3 in terms of a.
Calculation:
Step 1: From the given relation:
log10 a = m
⇒ 10m = a
Step 2: Expand 105m−3:
105m−3 = 105m × 10−3
Step 3: Replace 10m with a:
a5 = (10m)5 = 105m
So 105m−3 = a5 × 10−3
`10^(5m-3) = a^5/1000`
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Chapter 7: Logarithms - EXERCISE 7A [Page 72]
