Question

If excess of AgNO₃ solution is added to 100 mL of 0.024 M solution of dichlorobis (ethylene diamine) cobalt (III) chloride, how many moles of AgCl will be precipitated?

Options

• 0.001 mol

• 0.0024 mol

• 0.0048 mol

• 0.024 mol

Answer 1

0.0024 mol

Explanation:

Moles of the complex = 100 × 10⁻³ × 0.024 = 0.0024 mol

The formula of the complex is [CoCl₂(en)₂]CI.

\[\ce{[CoCl2(en)2]Cl + AgNO3 -> AgCl ↓ + [CoCl2(en)2]NO3}\]

1 mol of the complex = 1 mol of AgCI

0.0024 mol of the complex = 0.0024 mol of AgCl