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Question
If compressibility factor of real gas is 1.05 at STP. What is molar volume of real gas?
Options
22.40 dm³
21.33 dm³
23.52 dm³
23.05 dm³
MCQ
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Solution
23.52 dm³
Explanation:
Compressibility factor (Z) = 1.05
Under ideal condition, 1 mole of gas accupies
22.4 L volume.
\[Z=\frac{\mathrm{V}_{\mathrm{real}}}{\mathrm{V}_{\mathrm{ideal}}}\]
\[1.05=\frac{\mathrm{V_{real}}}{\mathrm{V_{ideal}}}=\frac{\mathrm{V_{real}}}{22.4\mathrm{dm^{3}}}\]
Vreal = 1.05 × 22.4 dm³ = 23.52 dm³
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Deviation from Ideal Behaviour
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