In NaCl, chlorine is in the −1 oxidation state.
In NaClO3, chlorine is in the +5 oxidation state.
Thus, the two oxidation states of chlorine in the products are −1 and +5.
If chlorine gas is passed through hot and conc. aqueous sodium hydroxide solution, the products formed have chlorine in different oxidation states. These oxidation states are indicated as:
−1 and +5
−1 and +3
−1 and +1
+1 and +5
−1 and +5
Explanation:
When chlorine gas reacts with hot, concentrated NaOH, a disproportionation reaction occurs:
\[\ce{3Cl2 + 6NaOH -> 5NaCl + NaClO3 + 3H2O}\]
In NaCl, chlorine is in the −1 oxidation state.
In NaClO3, chlorine is in the +5 oxidation state.
Thus, the two oxidation states of chlorine in the products are −1 and +5.