Advertisements
Advertisements
Question
If the area of the triangle formed by the points (x, 2x), (−2, 6) and (3, 1) is 5 square units , then x =
Options
- \[\frac{2}{3}\]
- \[\frac{3}{5}\]
3
5
Advertisements
Solution
We have the co-ordinates of the vertices of the triangle as A (x , 2x) ; B (-2 , 6) ; C ( 3 , 1) which has an area of 5 sq.units.
In general if `A (x_1 ,y_1 ) ; B (x_2 ,y_2) ; C (x_3 , y_3)` are non-collinear points then area of the triangle formed is given by-,
`"ar"(ΔABC ) = 1/2 |x_1(y_2 -y_3) + x_2 (y_3 - y_1 ) + x_3 (y_1 - y_2 )|`
So,
`5 = 1/2 |x(6-1)-2(1-2x)+3(2x - 6)|`
`5 = 1/2|15x - 20|`
Simplify the modulus function to get,
`3x - 4 = +-2`
`x = (4+-2)/3`
Therefore,
`x =2 , 2/3`
APPEARS IN
RELATED QUESTIONS
Let ABCD be a square of side 2a. Find the coordinates of the vertices of this square when The centre of the square is at the origin and coordinate axes are parallel to the sides AB and AD respectively.
Prove that the points (3, 0), (4, 5), (-1, 4) and (-2, -1), taken in order, form a rhombus.
Also, find its area.
If the coordinates of the mid-points of the sides of a triangle be (3, -2), (-3, 1) and (4, -3), then find the coordinates of its vertices.
Show that the following points are the vertices of a square:
A (0,-2), B(3,1), C(0,4) and D(-3,1)
Show that the following points are the vertices of a rectangle
A (0,-4), B(6,2), C(3,5) and D(-3,-1)
Find the ratio in which the point P(m, 6) divides the join of A(-4, 3) and B(2, 8) Also, find the value of m.
In what ratio does the line x - y - 2 = 0 divide the line segment joining the points A (3, 1) and B (8, 9)?
If the points P (a,-11) , Q (5,b) ,R (2,15) and S (1,1). are the vertices of a parallelogram PQRS, find the values of a and b.
Point P(x, 4) lies on the line segment joining the points A(−5, 8) and B(4, −10). Find the ratio in which point P divides the line segment AB. Also find the value of x.
The perpendicular distance of the P (4,3) from y-axis is
If (a,b) is the mid-point of the line segment joining the points A (10, - 6) , B (k,4) and a - 2b = 18 , find the value of k and the distance AB.
Find the value of k if points A(k, 3), B(6, −2) and C(−3, 4) are collinear.
What is the area of the triangle formed by the points O (0, 0), A (6, 0) and B (0, 4)?
Find the distance between the points \[\left( - \frac{8}{5}, 2 \right)\] and \[\left( \frac{2}{5}, 2 \right)\] .
If A (2, 2), B (−4, −4) and C (5, −8) are the vertices of a triangle, than the length of the median through vertex C is
The length of a line segment joining A (2, −3) and B is 10 units. If the abscissa of B is 10 units, then its ordinates can be

In the above figure, seg PA, seg QB and RC are perpendicular to seg AC. From the information given in the figure, prove that: `1/x + 1/y = 1/z`
If the coordinates of the two points are P(–2, 3) and Q(–3, 5), then (abscissa of P) – (abscissa of Q) is ______.
Which of the points P(0, 3), Q(1, 0), R(0, –1), S(–5, 0), T(1, 2) do not lie on the x-axis?
If the coordinate of point A on the number line is –1 and that of point B is 6, then find d(A, B).
