Question

If `int_a^b x^3 dx` = 0, then `(x^4/square)_a^b` = 0

⇒ `1/4 (square - square)` = 0

⇒ b⁴ – `square` = 0

⇒ (b² – a²)(`square` + `square`) = 0

⇒ b² – `square` = 0 as a² + b² ≠ 0

⇒ b = ± `square`

Answer 1

`int_a^b x^3 dx` = 0, then `(x^4/bb4)_a^b` = 0

⇒ `1/4` (b⁴ – a⁴) = 0

⇒ b⁴ – a⁴ = 0

⇒ (b² – a²)(b² + a²) = 0

⇒ b² – a² = 0 as a² + b² ≠ 0

⇒ b = ± a