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Question
If a fair coin is tossed twice, find the probability of getting 'almost one head'.
Sum
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Solution
If a coin is tossed twice, then possible outcomes
{(H, T), (H, H), (T, H), (T, T)}
Total number of outcomes = 4
Number of favourable outcomes = 3
({(T, H), (H, T), (T, T)})
∴ Required probability = `3/4`
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