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Tamil Nadu Board of Secondary EducationHSC Science Class 11

If A + B + C = 180°, prove that ABBCCAtan A2 tan B2+tan B2tan C2+tan C2tan A2 = 1 - Mathematics

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Question

If A + B + C = 180°, prove that `tan  "A"/2  tan  "B"/2 + tan  "B"/2 tan  "C"/2 + tan  "C"/2 tan  "A"/2` = 1

Sum
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Solution

Given A + B + C = 180°

⇒ `("A" + "" + "C")/2` = 90°

So `tan(("A" + "B")/2) = tan(90^circ - "C"/2) = cot  "C"/2`

(i.e) `(tan  "A"/2 + tan  "B"/2)/(1 - tan  "A"/2  tan  "B"/2) = cot  "C"/2 = 1/(tan  "C"/2)`

⇒ `(tan  "A"/2 + tan  "B"/2)tan  "C"/2 = 1 - tan  "A"/2 tan  "B"/2`

(i.e) `tan  "A"/2 tan  "C"/2 + tan  "B"/2 tan  "C"/2 = 1 - tan  "A"/2 tan  "B"/2`

(i.e) `tan  "A"/2 tan  "B"/2 + tan  "B"/2 tan  "C"/2 + tan  "C"/2 tan  "A"/2` = 1

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Trigonometric Functions and Their Properties
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Chapter 3: Trigonometry - Exercise 3.7 [Page 124]

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Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 3 Trigonometry
Exercise 3.7 | Q 1. (v) | Page 124

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