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Question
If A and B are mutually exclusive events, P(A) = 0.35 and P(B) = 0.45, find P(A ∪ B)
Sum
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Solution
Given that P(A) = 0.35 and P(B) = 0.45
Since the events A and B are mutually exclusive then P(A ∩ B) = 0
P(A ∪ B) = P(A) + P(B) – P(A ∩ B)
= 0.35 + 0.45 – 0
= 0.80
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