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Question
If A = 45°, verify that `sin A = sqrt((1 - cos 2A)/2)`.
Sum
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Solution
Given: A = 45°
Step-wise calculation:
1. Left side: sin A = sin 45°
= `1/sqrt(2)`
= `sqrt(2)/2`
2. Right side: `sqrt((1 - cos 2A)/2`.
Since 2A = 90°, cos 90° = 0.
So, `sqrt((1 - cos 2A)/2`
= `sqrt((1 - 0)/2`
= `sqrt(1/2)`
= `1/sqrt(2)`
= `sqrt(2)/2`
3. Because A = 45° is in the first quadrant sin A is positive, so taking the positive square root is correct.
`sin A = sqrt((1 - cos 2A)/2` holds for A = 45° both sides = `sqrt(2)/2`.
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Chapter 18: Trigonometric Ratios of Some Standard Angles and Complementary Angles - Exercise 18A [Page 373]
