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If A = 30°; show that: 4 cos A cos (60° - A). cos (60° + A) = cos 3A - Mathematics

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Question

If A = 30°;
show that:
4 cos A cos (60° - A). cos (60° + A) = cos 3A

Sum
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Solution

Given that A = 30°

LHS  = 4 cos A cos (60° – A ). cos (60° + A)

= 4 cos 30° cos (60° – 30°). cos (60° + 30°)

= 4 cos 30° cos 30° cos 90°

= `4(sqrt3/2)(sqrt3/2) (0)`

= 0

RHS = cos 3A

= cos3(30°)

= cos 90°

=0

LHS = RHS

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Chapter 23: Trigonometrical Ratios of Standard Angles [Including Evaluation of an Expression Involving Trigonometric Ratios] - Exercise 23 (B) [Page 293]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 23 Trigonometrical Ratios of Standard Angles [Including Evaluation of an Expression Involving Trigonometric Ratios]
Exercise 23 (B) | Q 4.6 | Page 293
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