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Question
If A = `[(2, 3),(0, -1)], B = [(-8),(8)]`, find a matrix M such that 2AM = B.
Sum
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Solution
Given
A = `[(2, 3),(0, -1)]`
B = `[(-8),(8)]`
We are to find a column matrix M = `[(x),(y)]` such that,
2AM = B
Step 1: Divide both sides by 2
AM = `1/2B`
= `1/2 [(-8),(8)]`
= `[(-4),(4)]`
Step 2: Compute AM
AM = `[(2, 3),(0, -1)] xx [(x),(y)]`
= `[(2x + 3y),(-y)]`
We are told
AM = `[(-4),(4)]`
Step 3: Equate components
2x + 3y = −4 ...(1)
−y = 4
y = −4 ...(2)
Substitute y = −4 into (1):
2x + 3y = −4
2x + 3(−4) = −4
2x − 12 = −4
2x = −4 + 12
2x = 8
x = `8/2`
x = 4
The matrix M = `[(4),(-4)]`
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