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Question
If A = `[(1, 2), (-1, -2)]`, B = `[(2, a), (-1, b)]` and if (A + B)2 = A2 + B2, find value of a and b.
Sum
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Solution
(A + B)2 = A2 + B2
∴ (A + B) (A + B) = A2 + B2
∴ A2 + AB + BA + B2 = A2 + B2
∴ AB + BA = 0
∴ AB = −BA
∴ `[(1, 2), (-1, -2)] [(2, a), (-1, b)] = - [(2, a), (-1, b)] [(1, 2), (-1, -2)]`
∴ `[(2 - 2, a + 2b), (-2 + 2, -a - 2b)] = -[(2 - a, 4 - 2a), (-1 - b, -2 - 2b)]`
∴ `[(0, a + 2b), (0, -a - 2b)] = [(a - 2, 2a - 4), (1 + b, 2 + 2b)]`
By the equality of matrices, we get
0 = a − 2 ...(1)
0 = 1 + b ...(2)
a + 2b = 2a − 4 ...(3)
− a − 2b = 2 + 2b ...(4)
From equations (1) and (2), we get
a = 2 and b = − 1
The values of a and b satisfy equations (3) and (4) also.
Hence, a = 2 and b = − 1.
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