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If a = 10^3 ร— 0.0048 and b = 10^โ€“1 ร— 75, find the values of โˆš๐‘Žโข๐‘ and โˆš๐‘Ž/๐‘. - Mathematics

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Question

If a = 103 × 0.0048 and b = 10–1 × 75, find the values of `sqrt(ab)` and `sqrt(a/b)`.

Sum
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Solution

We are given:

a = 103 × 0.0048,

b = 10–1 × 75

And asked to find `sqrt(ab)` and `sqrt(a/b)`

Step 1: Simplify a

a = 103 × 0.0048

= 1000 × 0.0048

= 4.8

Step 2: Simplify b

b = 10–1 × 75

= `1/10 xx 75`

= 7.5

Step 3: Compute ab

ab = 4.8 × 7.5 = 36

So, `sqrt(ab) = sqrt(36) = 6`

Step 4: Compute `a/b`

`a/b = 4.8/7.5 = 48/75 = 16/25`

So, `sqrt(a/b) = sqrt(16/25) = 4/5`

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Chapter 6: Indices - MISCELLANEOUS EXERCISE [Page 69]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 6 Indices
MISCELLANEOUS EXERCISE | Q 7. | Page 69
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