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Question
If 19th term of a non-zero arithmetic progression (AP) is zero, then its (49th term) : (29th term) is
Options
2 : 1
4 : 1
1 : 3
3 : 1
MCQ
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Solution
3 : 1
Explanation:
Given a19 = 0 ⇒ a + 18 d = 0 ⇒ a = – 18 d
Now `a_49/a_29 = (a + 48 d)/(a + 28 d) = (- 18d + 48d)/(- 18d + 28d) = (30d)/(10d)` = 3 : 1
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Apply Arithmetic Operations Using Modular Arithmetic Rules
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