Question

How much is y⁴ – 12y² + y + 14 greater than 17y³ + 34y² – 51y + 68?

Answer 1

Required expression is

y⁴ – 12y² + y + 14 – (17y³ + 34y² – 51y + 68)

= y⁴ – 12y² + y + 14 – 17y³ – 34y² + 51y – 68

On combining the like terms,

= y⁴ – 12y² – 34y² + y + 51y + 14 – 68 – 17y³ 

= y⁴ – 46y² + 52y – 17y³ – 54

= y⁴ – 17y³ – 46y² + 52y – 54

So, y⁴ – 12y² + y + 14 is y⁴ – 17y³ – 46y² + 52y – 54 greater than 17y³ + 34y² – 51y + 68.