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Question
How much charge is required for the reduction of 1 mol of Zn2+ to Zn?
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Solution
Zn2+ + 2e- → Zn
Number of electrons involved = 2
Charge required for the reduction of Zn2+ = 2F
We know
1F = 96,487 C
Thus,
2F = 2 × 96487 = 1,92,974 C
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