Question

How much charge is required for the reduction of 1 mol of Zn²⁺ to Zn?

Answer 1

Zn²⁺ + 2e^- → Zn

Number of electrons involved = 2

Charge required for the reduction of Zn²⁺ = 2F

We know

1F = 96,487 C

Thus,

2F = 2 × 96487 = 1,92,974 C