Question

How many coulombs of electricity are required for reduction of 1 mole of Sn⁴⁺ to Sn²⁺?

Answer 1

The half-reaction is:

\[\ce{Sn^{4+} + 2e- -> Sn^{2+}}\]

Each mole of Sn⁴⁺ requires 2 moles of electrons for reduction.

Use faraday’s law

Charge (Q) = n × F

Where:

n = 2 mol e⁻

F = 96500 C/mol e⁻

Q = 2 × 96500

Q = 193000 C