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How is the molar mass of a non-volatile substance determined from the lowering of vapour pressure?

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Question

How is the molar mass of a non-volatile substance determined from the lowering of vapour pressure?

Long Answer
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Solution

The molar mass of a non-volatile solute can be determined using the relative lowering of vapour pressure as follows:

If w = mass of solute, W = mass of solvent, M = molecular mass of solvent, and M' = molecular mass of solute, we have

`(P^circ - P)/P^circ = (w/(M^'))/(W/M + w/(M^'))`

If the solution is very dilute, we have

`(P^circ - P)/P^circ = (w//M)/(W//M)`

`(P^circ - P)/P^circ = (wM)/(W * M^')`

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Chapter 1: Solutions - REVIEW EXERCISES [Page 98]

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Nootan Chemistry [English] Class 12 ISC
Chapter 1 Solutions
REVIEW EXERCISES | Q 2.49 | Page 98
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