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Question
Harry sets up a circuit as shown in Figure 7 below. He measures potential difference ‘V’ across the variable resistor R with an instrument Y. He also measures current ‘I’ flowing through R with another instrument X.

- Identify the instruments X and Y.
- Using the graph of V against I shown below, calculate

- emf (E) of the cell.
- Internal resistance (r) of the cell.
Numerical
Short Answer
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Solution
a. X is an ammeter, and Y is a voltmeter.
b. We know that,
V = E − Ir
1. From the graph, where I = 0,
We have,
V = 2.5 V
∴ 2.5 = E − 0 × r
⇒ E = 2.5 V
2. When V = 0,
We have,
I = 0.5 A
∴ 0 = 2.5 − 0.5 r
⇒ r = `2.5/0.5`
= 5 Ω
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