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Question
Gopal has some Rs. 100 shares of company A, paying 10% dividend. He sells a certain number of these shares at a discount of 20% and invests the proceeds in Rs. 100 shares at Rs. 60 of company B paying 20% dividend. If his income, from the shares sold, increases by Rs. 18,000, find the number of shares sold by Gopal.
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Solution
Let the number of share the man sold be x.
N.V of share = Rs. 100
Rate of dividend = 10%
Dividend on each share = 10% of Rs. 100 = Rs. 10
So, the dividend on x shares = Rs. 10 × x = Rs. 10x
Selling price of each share = Rs. 100 – 20% of Rs. 100 = Rs. 80
Amount obtained on selling x shares = Rs. 80 × x = Rs. 80x
The proceeds he invest in Rs. 100 shares at Rs. 60 of company B paying 20% dividend
N.V of share = Rs. 100
M.V of each share = Rs. 60
Number of shares bought by the man = `"Amount invested"/"M.V of each share"`
= `(80x)/60`
= `(4x)/3`
Dividend on each share = 20% of Rs. 100 = Rs. 20
Total dividend recieved = Dividend on each share × Number of shares
= `20 xx (4"x")/3`
= `(80x)/3`
Increase in the income = Rs. 18,000
⇒ `(80x)/3 - 10x = 18000`
⇒ `(50x)/3 = 18000`
x = Rs. 1080
Hence, the number of shares sold by Gopal is Rs. 1080.
