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Question
Gopal has some Rs. 100 shares of company A, paying 10% dividend. He sells a certain number of these shares at a discount of 20% and invests the proceeds in Rs. 100 shares at Rs. 60 of company B paying 20% dividend. If his income, from the shares, sold, increases by Rs. 18,000, find the number of shares sold by Gopal.
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Solution
Let the number of shares Gopal sold be x.
N.V. = ₹ 100
Rate of dividend = 10%
Dividend = No. of shares × Rate of div. × N.V. of 1 share
= `x xx 10/100 xx 100`
= 10x
S.P. = ₹ 100 − 20% of ₹ 100
= ₹ 100 − `20/100 xx 100`
= ₹ 100 − ₹ 20
= ₹ 80.
Amount obtained on selling x shares = ₹ 80x.
The proceeds he invested in ₹ 100 shares at ₹ 60 of company B paying 20% dividend.
N.V. = ₹ 100
M.V. = ₹ 60
No. of shares bought by man = `("Amount invested")/("M. V.") = (80x)/60 = (4x)/3`
Dividend = No. of shares × Rate of div. × N.V. of 1 share
= `(4x)/3 xx 20/100 xx 100`
= `(80x)/3`
Given, increase in income = ₹ 18000
∴ `(80x)/3 - 10x = 18000`
⇒ `(80x - 30x)/3 = 18000`
⇒ `(50x)/3 = 18000`
⇒ x = `(18000 xx 3)/50`
⇒ x = 1080
Hence, no. of shares sold by Gopal is 1080.
