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Given beside are the electrode potential values, E° for some of the first row transition elements: Explain the irregularities in these values on the basis of electronic structures of atoms. - Chemistry (Theory)

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Question

Given beside are the electrode potential values, E° for some of the first row transition elements:

Element \[\ce{E^\circ_{M^{n+}/M}}\] (V)
V (23) −1.18
Cr (24) −0.91
Mn (25) −1.18
Fe (26) −0.44
Co (27) −0.28
Ni (28) −0.25
Cu (29) +0.34

Explain the irregularities in these values on the basis of electronic structures of atoms.

Explain
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Solution

The electrode potential values (E°) for the first row transition elements show irregularities due to their electronic configurations:

Element \[\ce{E^\circ_{M^{n+}/M}}\] (V) Electronic configuration (Ground state)
V (23) −1.18 [Ar] 3d3 4s2
Cr (24) −0.91 [Ar] 3d5 4s1 (half-filled d-subshell)
Mn (25) −1.18 [Ar] 3d5 4s2
Fe (26) −0.44 [Ar] 3d6 4s2
Co (27) −0.28 [Ar] 3d7 4s2
Ni (28) −0.25 [Ar] 3d8 4s2
Cu (29) +0.34 [Ar] 3d10 4s1 (filled d-subshell)
  1. The stability of partially and fully filled d-subshells is the primary cause of the anomalies in electrode potentials.
  2. Compared to vanadium (V) and manganese (Mn), which have higher negative electrode potentials (−1.18 V), chromium (Cr) has a less negative electrode potential (−0.91 V) due to its more stable half-filled 3d5 configuration.
  3. Because of its completely filled 3d10 subshell, which is extremely stable and produces a positive electrode potential (+0.34 V), copper (Cu) is less susceptible to oxidation.
  4. Elements having less stable electronic structures, such as V and Mn, have higher negative electrode potentials, making them more easily oxidized.
  5. As we move from V to Cu, the increased stability of d-electrons leads electrode potentials to become less negative and eventually positive.
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Chapter 8: d-and ƒ-Block Elements - REVIEW EXERCISES [Page 478]

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Nootan Chemistry Part 1 and 2 [English] Class 12 ISC
Chapter 8 d-and ƒ-Block Elements
REVIEW EXERCISES | Q 8.33 | Page 478
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