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Given 3[xyzw]=[x6-12W]+[4x+yZ+W3] find the values of x, y, z and w. - Mathematics

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Question

Given `3[(x,y),(z,w)] = [(x,6),(-1,2W)] + [(4,x+y),(Z+W,3)]` find the values of x, y, z and w.

Sum
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Solution

Given: `3[("x", "y"),("z", "w")] = [("x",6), (-1, 2"w")] + [(4, "x + y"),("z + w" ,3)]`

`= [(3"x",3"y"),(3"z", 3"w")] = [("x" + 4, 6 + "x" + "y"),(-1 + "z" + "w", 2"w" +3)]`

On comparing corresponding elements

3x = x + 4

⇒ 2x = 4

⇒ x = 2

3y = 6 + x + y

⇒ 2y = 6 + x

= 6 + 2

⇒ y = 4

3 w = 2 w + 3

w = 3

3 z = -1 + z + w

⇒ 3z = -1 + w

= -1 + 3

z = 1

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Chapter 3: Matrices - Exercise 3.2 [Page 81]

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NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 3 Matrices
Exercise 3.2 | Q 12 | Page 81
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