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Question
From the velocity-time plot shown in the following figure, find the distance travelled by the particle during the first 40 seconds. Also find the average velocity during this period.

Short/Brief Note
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Solution
Area shown in the v–t graph gives the distance travelled.
∴ Distance travelled in the first 40 seconds = Area of ∆OAB + Area of ∆BCD
\[= \frac{1}{2} \times 5 \times 20 + \frac{1}{2} \times 5 \times 20 = 100 \text{ m } \]

As the displacement is zero, the average velocity is zero.
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