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Question
Four solid cubes, each of volume I 728 cm3, are kept in two rows having two cubes in each row. They form a rectangular solid with square base. The total surface area (in cm2) of the resulting solid is:
Options
576
1152
2304
1440
MCQ
Solution
2304
Explanation:
Four solid cubes, each of volume = 1728 crn3
`a^3` = 1728
∴ `x` = 12
After joining in two rows having two cubes in each row.
Now sides of rectangular solid are 12, 24 and 24.
Total surface area = 2(12 × 24 + 24 × 24 + 12 × 24)
= `2(24/2 xx 24 + (24)^2 + 24/2 xx 24)`
= `2(((24)^2 + 2(24)^2 + (24)^2)/2)`
= 4 × (24)2
= 22 × 242
= (48)2
= 2304
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Mensuration - Area and Volume (Entrance Exam)
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