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Four solid cubes, each of volume I 728 cm3, are kept in two rows having two cubes in each row. They form a rectangular solid with square base. The total surface area (in cm2) of the resulting solid -

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Question

Four solid cubes, each of volume I 728 cm3, are kept in two rows having two cubes in each row. They form a rectangular solid with square base. The total surface area (in cm2) of the resulting solid is:

Options

  • 576

  • 1152

  • 2304

  • 1440

MCQ

Solution

2304

Explanation:

Four solid cubes, each of volume = 1728 crn3 

`a^3` = 1728

∴ `x` = 12

After joining in two rows having two cubes in each row.


Now sides of rectangular solid are 12, 24 and 24.

Total surface area = 2(12 × 24 + 24 × 24 + 12 × 24)

= `2(24/2 xx 24 + (24)^2 + 24/2 xx 24)`

= `2(((24)^2 + 2(24)^2 + (24)^2)/2)`

= 4 × (24)2

= 22 × 242

= (48)2

= 2304

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Mensuration - Area and Volume (Entrance Exam)
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