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Question
Four points A (6, 3), B (−3, 5), C(4, −2) and D (x, 3x) are given in such a way that `(ΔDBG) /(ΔABG)=1/2,` find x
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Solution
GIVEN: four points A (6, 3), B (−3, 5) C (4, −2) and D(x, 3x) such that `(ΔDBC)/(ΔABC) `
TO FIND: the value of x
PROOF:
We know area of the triangles formed by three points(x1y1),(x2y2),and (x3y3) is given by `=1/2[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)`
Now
Area of triangle DBC taking D (x,3x),b(-3,5),c(4-2)
`triangleDBC=>1/2[x(5-(-2))+(-3)((-2)-3x)+(4)(3x-5)]`
`triangle DBC=>1/2[7x+6+9x+12x-20]`
`triangle =>1/2[28x-14]`
`triangle=>1/2[14(2x-1]) `
`triangle =>[7(2x-1)]` .......(1)
Area of triangle ABC taking,A(6,3),B(-3,5),C(4,-2)
`=>1/2[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]`
`=>1/2[6(5-(-2))+(-3)((-2)- 3)+(4)(3-5)]`
`=>1/2[6(7)+(-3)(-5)+(4)(-2)]`
`=>1/2[42+15-8]`
`=>49/2` .......(2)
Also it is given that
`(triangle DBC)/(triangleABC)=1/2`
Substituting the value from (1) and (2) we get
`(triangle DBC)/(triangleABC)=1/2`
`+-(7(2x-1))/(49/2)=1/2`
`2xx7(2x-1)/49=1/2or-2xx7((2x-1))/49=1/2`
`(2x-1)=1/2xx7/2or (-2x+1)=1/2xx7/2`
`2x=7/4+1 or 2x=7/4-1`
`2x=11/4 or 2x=(-3)/4 `
`x=11/8 or x=(-3)/8`
