Question

Four alternative answers for the following question is given. Choose the correct alternative.
Chords AB and CD of a circle intersect inside the circle at point E. If AE = 5.6, EB = 10, CE = 8, find ED.

Options

• 7

• 8

• 11.2

• 9

Answer 1

If two chords of a circle intersect each other in the interior of the circle, then the product of the lengths of the two tangents of one chord is equal to the product of the lengths of the two segments of the other chord.
∴ AE × EB = CE × ED
⇒ 5.6 × 10 = 8 × ED
⇒ ED = \[\frac{56}{8}\]  = 7 units
Hence, the correct answer is 7.