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Form the differential equation of the family of parabolas having vertex at origin and axis along positive y-axis. -

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Question

Form the differential equation of the family of parabolas having vertex at origin and axis along positive y-axis.

Options

  • `x  (dy)/(dx) - 2x` = 0

  • `x  (dy)/(dx) - 2y` = 0

  • `(dy)/(dx) - 2y` = 0

  • `(dy)/(dx) - x` = 0

MCQ

Solution

`x  (dy)/(dx) - 2y` = 0

Explanation:

The equation of a parabola with the vertex along the positive y-axis is-


`x^2 = 4ay`  .......(i)

Where (a) is the parameter 

Differentiating w.r.t. x

`2x = 4ay^1`  .......(ii)

Dividing (ii) by (i)

`(2x)/x^2 = (4ay)/(4ay)` ⇒ `y^-1/y = 2/x`

∴ `xy^1 = 2y`

Required differential equation is `x - 2y` = 0.

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