Advertisements
Advertisements
Question
Form the differential equation of the family of parabolas having vertex at origin and axis along positive y-axis.
Options
`x (dy)/(dx) - 2x` = 0
`x (dy)/(dx) - 2y` = 0
`(dy)/(dx) - 2y` = 0
`(dy)/(dx) - x` = 0
MCQ
Solution
`x (dy)/(dx) - 2y` = 0
Explanation:
The equation of a parabola with the vertex along the positive y-axis is-
`x^2 = 4ay` .......(i)
Where (a) is the parameter
Differentiating w.r.t. x
`2x = 4ay^1` .......(ii)
Dividing (ii) by (i)
`(2x)/x^2 = (4ay)/(4ay)` ⇒ `y^-1/y = 2/x`
∴ `xy^1 = 2y`
Required differential equation is `x - 2y` = 0.
shaalaa.com
Is there an error in this question or solution?