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Question
For what k.e of neutron will the associated de-Broglie wavelength be 1.40 × 10-10 m? mass of neutron= 1.675 × 10-27 kg, h = 6.63 × 10-34 J
Options
6.634 × 10-21 J
4.262 × 10-19 J
1.2 × 10-10 m
2.5 × 10-19 J
MCQ
Solution
6.634 × 10-21 J
Explanation:
`lambda = h/sqrt(2ME)` or E = `h^2/(2lambda2m)`
= `(6.63 xx 10^-34)^2/(2 xx (1.4 xx 10^-10)^2 xx (1.674 xx 10)^-27`
= 6.634 × 10-21 J.
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