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For two vectors veca and vecb Assertion (A): |vecaxxvecb|^2+(veca*vecb)^2=|veca|^2|vecb|^2 Reason (R): |vecaxxvecb|=(veca*vecb)tantheta,(theta≠pi/2)

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Question

For two vectors `veca` and `vecb`

Assertion (A): `|vecaxxvecb|^2+(veca*vecb)^2=|veca|^2|vecb|^2`

Reason (R): `|vecaxxvecb|=(veca*vecb)tantheta,(theta≠pi/2)`

Options

  • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).

  • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).

  • Assertion (A) is true, but Reason (R) is false.

  • Assertion (A) is false, but Reason (R) is true.

MCQ
Assertion and Reasoning
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Solution

Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).

Explanation:

`|vecaxxvecb|=|veca||vecb|sin theta`

`|vecaxxvecb|^2=|veca|^2|vecb|^2sin^2theta`

`|veca*vecb|=|veca||vecb|costheta`

`|vecaxxvecb|^2=|veca|^2|vecb|^2cos^2theta`

`|vecaxxvecb|^2+(veca*vecb)^2=|veca|^2|vecb|^2sin^2theta+|veca|^2|vecb|^2cos^2theta`

= `|veca|^2|vecb|^2sin^2+cos^2theta`

Since sin2θ + cos2θ = 1, we get:

`|vecaxxvecb|^2+(veca*vecb)^2=|veca|^2|vecb|^2`

`|vecaxxvecb|/(veca*vecb)=(|veca||vecb|sintheta)/(|veca||vecb|costheta)`

= tanθ

`|vecaxxvecb|=(veca*vecb)tanθ`

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2025-2026 (March) 65/2/1
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