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Question
For the reaction, A + B → Products, the rate law is Rate = k [A]2/3 [B]2. What are the units of rate constant?
Numerical
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Solution
Given:
Rate = k [A]2/3 [B]2
Rate has units of mol L−1 s−1 = concentration × time−1
overall order = \[\ce{\frac{2}{3} + 2 = \frac{8}{3}}\]
Units of rate constant k = \[\ce{\frac{Rate}{[A]^{2/3} [B]^2}}\]
= \[\ce{\frac{conc. time^{-1}}{[conc.]^{8/3}}}\]
= \[\ce{[conc]^{1 − 8/3} * time^{-1}}\]
= [conc]−5/3 . time−1
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Chapter 4: Chemical Kinetics - REVIEW EXERCISES [Page 231]
