Question

For reaction \[\ce{2N2O5 -> 2NO2 + O2}\], the rate and rate constants are 1.02 × 10⁻⁴ mol litre⁻¹ sec⁻¹ and 3 4 × 10⁻⁵ sec⁻¹. respectively. The concentration of N₂O₅ at that time will be:

Options

• 1.732 mol L⁻¹

• 3 mol L⁻¹

• 1.02 × 10⁻⁴ mol L⁻¹

• 3.2 × 10⁵ mol L⁻¹

Answer 1

3 mol L⁻¹

Explanation:

Given: The given reaction is \[\ce{2N2O5 -> 2NO2 + O2}\]

Rate = 1.02 × 10⁻⁴ mol L⁻¹ s⁻¹

k = 3 4 × 10⁻⁵ sec⁻¹

For a first order reaction:

Rate = k [N₂O₅]

N₂O₅ = `"Rate"/k`

= `(1.02 xx 10^-4)/(3.4 xx 10^-5)`

= 0.3 × 10

= 3.0 mol L⁻¹