English

For a zero order reaction molecularity can never be equal to zero. Explain. - Chemistry

Advertisements
Advertisements

Question

For a zero-order reaction, molecularity can never be equal to zero. Explain.

Short/Brief Note
Advertisements

Solution

  1. The order of a chemical reaction is experimentally determined. Hence, the order can be zero.
  2. Molecularity refers to how many reactant molecules are involved in reactions.
  3. The number of molecules in any reaction cannot be zero.
    Hence, for a zero-order reaction molecularity can never be equal to zero.
shaalaa.com
Molecularity of Elementary Reactions
  Is there an error in this question or solution?
Chapter 6: Chemical Kinetics - Short answer questions (Type- II)

APPEARS IN

SCERT Maharashtra Chemistry [English] 12 Standard HSC
Chapter 6 Chemical Kinetics
Short answer questions (Type- II) | Q 7

RELATED QUESTIONS

Identify molecularity of following reaction:

\[\ce{C2H5I_{(g)} -> C2H_{4(g)} + HI_{(g)}}\]


Name the slowest step that determines the rate in a complex reaction.


Write an expression for instantaneous rate of reaction:

2N2O(g) → 4NO2(g) + O2(g).

What is the order of reaction?


Why is molecularity applicable for only elementary reactions whereas order of a reaction is applicable for elementary and complex reactions? Explain with suitable examples.


Give one example of the reaction where order and molecularity are the same. 
Mention any two factors that influence the rate of chemical reaction.
If for the reaction A → products, a straight line graph passing through origin is obtained between the rate of reaction against concentration of A, what would be the order of reaction? Why?


For the elementary reaction

\[\ce{2SO2(g) + O2(g) -> 2SO3(g)}\], identify the correct among the following relations.


The rate determining step of a reaction is the step ____________.


For the elementary reaction, \[\ce{3H2_{(g)} + N2_{(g)} -> 2NH3_{(g)}}\] identify the correct relation among the following relations.


For the reaction \[\ce{2NO2 + F2 -> 2NO2F}\], following mechanism has been provided:

\[\ce{NO2 + F2 ->[slow] NO2F + F}\]

\[\ce{NO2 + F ->[fast] NO2F}\]

The rate expression of the above reaction can be written as:


The reaction \[\ce{2NO2Cl_{(g)} -> 2NO2_{(g)} + Cl2_{(g)}}\] takes place in two steps as

(i) \[\ce{NO2Cl_{(g)} -> NO2_{(g)} + Cl_{(g)}}\]

(ii) \[\ce{NO2Cl_{(g)} + Cl_{(g)} -> NO2_{(g)} + Cl2_{(g)}}\]

Identify the reaction intermediate.


A chemical species that is formed in one elementary step in the mechanism of complex reaction and consumed in the subsequent step is called ____________.


A reaction involving two different reactants can never be a ______


Identify the molecularity of following elementary reaction:

NO(g) + O3(g) → NO3(g) + O(g)


A certain reaction occurs in two steps as

(i) \[\ce{2SO2(g) + 2NO2(g) -> 2SO3(g) + 2NO(g)}\]

(ii) \[\ce{2NO(g) + O2(g) -> 2NO2(g)}\]

In the reaction:


What is an elementary reaction?


How does a catalyst differ from reaction intermediate?


Find out the reaction intermediate and molecularity of the following reactions.
\[\ce{NO_{(g)} + Cl2_{(g)} -> NOCl_{2(g)}}\]

\[\ce{NOCl_{2(g)} + NO_{(g)} -> 2NOCl_{(g)}}\]

Draw the structure of BrF5 and HOCl.


Define molecularity of reaction.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×