Advertisements
Advertisements
Question
For a first-order reaction, the rate constant is 6.909 min−1 the time taken for 75% conversion in minutes is
Options
`(3/2) log 2`
`(2/3) log 2`
`(3/2) log (3/4)`
`(2/3) log (4/3)`
Advertisements
Solution
`(2/3) log 2`
APPEARS IN
RELATED QUESTIONS
The rate of catalysed reaction is large than the uncatalysed reaction as _______.
Write a mathematical expression for integrated rate law for zero-order reaction.
The time for half change in a first order decomposition of a substance A is 60 seconds. Calculate the rate constant. How much of A will be left after 180 seconds?
The rate of the reaction \[\ce{A + B -> C}\] is 3.6 × 10−2 mol dm−3 s−1 when [A] = 0.3 mol dm−3 and [B] = 0.2 mol dm−3. Calculate k if reaction is first order in A and zero order in B.
For the first order reaction, plot of log10 [A]t against time 't' is a straight line with a negative slope equal to ____________.
For first order reaction the slope of the graph of log10 [A]t Vs. time is equal to ____________.
A first order reaction, A → B takes 100 minutes for it's 90% completion. What is the rate constant of reaction?
Which is the unit of rate constant for the first-order reaction if time is expressed in seconds?
If the rate constant for a first-order reaction is k, the time (t) required for the completion of 99% of the reaction is given by:
What is the rate constant of a first order reaction if 0.08 mole of reactant reduces to 0.02 mole in 23.03 minutes?
