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Question
For a cell given below:
\[\ce{Ag | Ag+ || Cu^2+ | Cu}\]
\[\ce{Ag+ + e- -> Ag}\]; E° = x
\[\ce{Cu^2+ + 2e- -> Cu}\]; E° = y
\[\ce{E{^{\circ}_{cell}}}\] is ______.
Options
x + 2y
2x + y
y − x
y − 2x
MCQ
Fill in the Blanks
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Solution
\[\ce{E{^{\circ}_{cell}}}\] is y − x.
Explanation:
The standard cell potential is calculated using the relation:
\[\ce{E{^{\circ}_{cell}} = E{^{\circ}_{cathode}} - E{^{\circ}_{anode}}}\]
In this cell, the cathode is the Cu2+/Cu electrode with E° = y, and the anode is the Ag+/Ag electrode with E° = x.
Therefore, \[\ce{E{^{\circ}_{cell}} = y - x}\]
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