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Question
Five cards, the ten, jack, queen, king, and ace of diamonds, are well-shuffled with their face downwards. One card is then picked up at random.
If the queen is drawn and put aside, what is the probability that the second card picked up is (a) an ace? (b) a queen?
Sum
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Solution
The queen is drawn and put aside.
∴ Only 5 − 1 = 4 cards are left
Total number of possible outcomes = 4
(a) Total number of aces = 1
P (getting an ace) = `1/4`
(b) As queen is already drawn, therefore, the number of queens will be 0.
∴ Number of favourable outcomes= 0
P (getting a queen) = `0/4 = 0`
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