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Find the zeroes of the quadratic polynomial f(x) = 4x2 - 4x - 3 and verify the relation between its zeroes and coefficients. - Mathematics

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Question

Find the zeroes of the quadratic polynomial f(x) = 4x2 - 4x - 3 and verify the relation between its zeroes and coefficients.

Sum
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Solution

We have:

f(x) = 4x2 - 4x - 3

= 4x2 ˗ (6x ˗ 2x) ˗ 3

= 4x2 ˗ 6x + 2x ˗ 3

= 2x (2x ˗ 3) + 1(2x ˗ 3)

= (2x + 1) (2x ˗ 3)

∴ f(x) = 0 ⇒ (2x + 1) (2x ˗ 3) = 0

⇒ 2x + 1= 0 or 2x ˗ 3 = 0`

⇒ `x = (-1)/2 or x =3/2` 

So, the zeroes of f(x) are `(-1)/2 and 3/2` 

Sum of zeroes = `(-1/2)+(3/2)=(-1+3)/2=2/2=1="-(Coefficient of  x)"/(("Coefficient of"  x^2))` 

Product of zeroes =`((-1)/2)xx(3/2)=(-3)/4= "Constant term"/(("Coefficient of"  x^2))`

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Chapter 2: Polynomials - Exercises 1

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 2 Polynomials
Exercises 1 | Q 4

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