Question

Find the x and y intercept of the following line:

2x − 3y + 12 = 0

Answer 1

Given equation of the line is 2x − 3y + 12 = 0

∴ 2x − 3y = − 12

∴ `(2x)/((-12)) - (3y)/((-12))` = 1

∴ `x/(-6) + y/4` = 1

This is of the form `x/"a" + y/"b"` = 1,

where x-intercept = a, y-intercept = b

∴ x-intercept = − 6 and y-intercept = 4