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Question
Find the values of x, y and z from the following equation
`[(x + y, 2),(5 + z, xy)] = [(6, 2),(5, 8)]`
Sum
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Solution
x + y = 6 ...(1)
5 + z = 5
z = 5 – 5 = 0
xy = 8
y = `8/x`
Substitute the value of y = `8/x` in (1)
`x + 8/x` = 6
x2 + 8 = 6x
x2 – 6x + 8 = 0
(x – 4) (x – 2) = 0
∴ x – 4 = 0 or x – 2 = 0
x = 4 or x = 2
y = `8/4` = 2 or y = `8/2` = 4

∴ The value of x, y and z are 4, 2, 0 or 2, 4, 0
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Chapter 3: Algebra - Exercise 3.16 [Page 144]
