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Question
Find the values of k so that the sum of tire roots of the quadratic equation is equal to the product of the roots in each of the following:
kx2 + 2x + 3k = 0
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Solution
kx2 + 2x + 3k = 0.
Here, a = k, b = 2, and c = 3k.
Sum of roots = `-b/a = -(2)/k`
Product of root = `c/a`
= `(3k)/k`
= 3
Sum of roots = Product of roots
`-(2)/k = 3`
⇒ 3k = -2
⇒ k = `-(2)/(3)`.
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