Question

Find the values of following polynomials at m = 1, n = –1 and p = 2:

m²n² + n²p² + p²m²

Answer 1

Given, m = 1, n = –1 and p = 2

So, putting m = 1, n = –1 and p = 2 in the given expressions, we get

m²n² + n²p² + p²m² = (1)²(–1)² + (–1)²(2)² + (2)²(1)² 

= 1 + 4 + 4

= 9